4x^2-16x+16=121

Solution for 4x^2-16x+16=121 equation:

4x^2-16x+16=121

We move all terms to the left:

4x^2-16x+16-(121)=0

We add all the numbers together, and all the variables

4x^2-16x-105=0

a = 4; b = -16; c = -105;
Δ = b2-4ac
Δ = -162-4·4·(-105)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-44}{2*4}=\frac{-28}{8}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+44}{2*4}=\frac{60}{8}
=7+1/2
$